A mixture of 80 liters contains two liquids P and Q in the ratio 2:5. How much l

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Question: A mixture of 80 liters contains two liquids P and Q in the ratio 2:5. How much liquid P is in the mixture?

Options:

Correct Answer: 20 liters

Solution:

In a 2:5 ratio, the total parts = 2 + 5 = 7. Liquid P = (2/7) * 80 = 22.86 liters (approx 23 liters).

A mixture of 80 liters contains two liquids P and Q in the ratio 2:5. How much liquid P is in the mixture?

A mixture of 80 liters contains two liquids P and Q in the ratio 2:5. How much liquid P is in the mixture?

Step 1: Understand the ratio of liquids P and Q, which is 2:5.
Step 2: Add the parts of the ratio together: 2 (for P) + 5 (for Q) = 7 parts total.
Step 3: Find out how much one part is worth by dividing the total volume of the mixture (80 liters) by the total parts (7): 80 / 7 = approximately 11.43 liters per part.
Step 4: Calculate the amount of liquid P by multiplying the number of parts for P (which is 2) by the value of one part: 2 * 11.43 = approximately 22.86 liters.
Step 5: Round the answer to the nearest whole number if needed: 22.86 liters is approximately 23 liters.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Basic Arithmetic – Performing calculations involving addition, multiplication, and division.