A mixture of 50 liters contains two liquids X and Y in the ratio 7:3. How much l

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Question: A mixture of 50 liters contains two liquids X and Y in the ratio 7:3. How much liquid Y is in the mixture?

Options:

Correct Answer: 20 liters

Solution:

In a 7:3 ratio, the total parts = 7 + 3 = 10. Liquid Y = (3/10) * 50 = 15 liters.

A mixture of 50 liters contains two liquids X and Y in the ratio 7:3. How much liquid Y is in the mixture?

A mixture of 50 liters contains two liquids X and Y in the ratio 7:3. How much liquid Y is in the mixture?

Step 1: Understand that the total mixture is 50 liters.
Step 2: Know that the ratio of liquid X to liquid Y is 7:3.
Step 3: Add the parts of the ratio together: 7 (for X) + 3 (for Y) = 10 parts total.
Step 4: Find out how much one part is by dividing the total volume by the total parts: 50 liters / 10 parts = 5 liters per part.
Step 5: Since liquid Y has 3 parts, multiply the volume of one part by the number of parts for Y: 5 liters/part * 3 parts = 15 liters.
Step 6: Conclude that there are 15 liters of liquid Y in the mixture.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Basic Arithmetic – Performing multiplication and division to find the quantity of a component in a mixture.