If 30 liters of a mixture contains alcohol and water in the ratio 1:2, how much

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Question: If 30 liters of a mixture contains alcohol and water in the ratio 1:2, how much alcohol is in the mixture?

Options:

Correct Answer: 10 liters

Solution:

In a 1:2 ratio, the total parts = 1 + 2 = 3. Alcohol = (1/3) * 30 = 10 liters.

If 30 liters of a mixture contains alcohol and water in the ratio 1:2, how much alcohol is in the mixture?

If 30 liters of a mixture contains alcohol and water in the ratio 1:2, how much alcohol is in the mixture?

Step 1: Understand the ratio of alcohol to water, which is 1:2.
Step 2: Add the parts of the ratio together: 1 (for alcohol) + 2 (for water) = 3 parts total.
Step 3: Determine how much one part is worth by dividing the total volume of the mixture (30 liters) by the total parts (3): 30 liters / 3 parts = 10 liters per part.
Step 4: Since alcohol is 1 part, multiply the value of one part (10 liters) by the number of parts for alcohol (1): 10 liters * 1 = 10 liters of alcohol.

Ratio and Proportion – Understanding how to divide a total quantity based on a given ratio.
Mixture Problems – Calculating the components of a mixture based on their ratios.