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In a thin lens, if the object distance is 15 cm and the image distance is 10 cm,

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Question: In a thin lens, if the object distance is 15 cm and the image distance is 10 cm, what is the magnification?

Options:

  1. 0.67
  2. 1.5
  3. 1
  4. 2

Correct Answer: 1.5

Solution: 

Magnification (m) is given by m = -v/u. Here, m = -10/15 = -2/3, which means the magnification is 1.5 in absolute value.

In a thin lens, if the object distance is 15 cm and the image distance is 10 cm,

Practice Questions

Q1
In a thin lens, if the object distance is 15 cm and the image distance is 10 cm, what is the magnification?
  1. 0.67
  2. 1.5
  3. 1
  4. 2

Questions & Step-by-Step Solutions

In a thin lens, if the object distance is 15 cm and the image distance is 10 cm, what is the magnification?
Correct Answer: 1.5
  • Step 1: Identify the object distance (u) and the image distance (v). Here, u = 15 cm and v = 10 cm.
  • Step 2: Use the magnification formula, which is m = -v/u.
  • Step 3: Substitute the values into the formula: m = -10/15.
  • Step 4: Simplify the fraction: -10/15 can be reduced to -2/3.
  • Step 5: The absolute value of magnification is |m| = 2/3, which is approximately 0.67.
  • Thin Lens Formula – Understanding the relationship between object distance (u), image distance (v), and magnification (m) in thin lenses.
  • Magnification Calculation – Calculating magnification using the formula m = -v/u and interpreting the sign and absolute value.
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