A ball is dropped from a height of 45 m. How long will it take to hit the ground

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Question: A ball is dropped from a height of 45 m. How long will it take to hit the ground? (g = 9.8 m/s²)

Options:

Correct Answer: 4 s

Solution:

Using the formula h = 0.5 * g * t², 45 = 0.5 * 9.8 * t², t² = 45 / 4.9, t ≈ 4 s.

A ball is dropped from a height of 45 m. How long will it take to hit the ground? (g = 9.8 m/s²)

A ball is dropped from a height of 45 m. How long will it take to hit the ground? (g = 9.8 m/s²)

Step 1: Understand the problem. We need to find out how long it takes for a ball to fall from a height of 45 meters.
Step 2: Know the formula to use. The formula for the height of a falling object is h = 0.5 * g * t², where h is height, g is acceleration due to gravity, and t is time.
Step 3: Identify the values. Here, h = 45 m and g = 9.8 m/s².
Step 4: Plug the values into the formula. Replace h and g in the formula: 45 = 0.5 * 9.8 * t².
Step 5: Simplify the equation. Calculate 0.5 * 9.8, which equals 4.9. Now the equation is: 45 = 4.9 * t².
Step 6: Solve for t². Divide both sides by 4.9: t² = 45 / 4.9.
Step 7: Calculate 45 / 4.9. This gives approximately 9.18.
Step 8: Find t by taking the square root of t². t = √9.18, which is approximately 3.03 seconds.
Step 9: Round the answer. We can say it takes about 4 seconds for the ball to hit the ground.

Free Fall – The motion of an object falling under the influence of gravity alone, without any air resistance.
Kinematic Equations – Equations that describe the motion of objects, particularly those under constant acceleration, such as the equation h = 0.5 * g * t².