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If a tank is filled by a pipe in 5 hours and emptied by another pipe in 10 hours

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Question: If a tank is filled by a pipe in 5 hours and emptied by another pipe in 10 hours, how long will it take to fill the tank if both pipes are opened together?

Options:

  1. 3 hours
  2. 4 hours
  3. 5 hours
  4. 6 hours

Correct Answer: 4 hours

Solution:

The net rate is 1/5 - 1/10 = 2/10 - 1/10 = 1/10. Therefore, it will take 10 hours to fill the tank.

If a tank is filled by a pipe in 5 hours and emptied by another pipe in 10 hours

Practice Questions

Q1
If a tank is filled by a pipe in 5 hours and emptied by another pipe in 10 hours, how long will it take to fill the tank if both pipes are opened together?
  1. 3 hours
  2. 4 hours
  3. 5 hours
  4. 6 hours

Questions & Step-by-Step Solutions

If a tank is filled by a pipe in 5 hours and emptied by another pipe in 10 hours, how long will it take to fill the tank if both pipes are opened together?
  • Step 1: Determine the rate at which the filling pipe fills the tank. If it fills the tank in 5 hours, its rate is 1 tank per 5 hours, or 1/5 of the tank per hour.
  • Step 2: Determine the rate at which the emptying pipe empties the tank. If it empties the tank in 10 hours, its rate is 1 tank per 10 hours, or 1/10 of the tank per hour.
  • Step 3: Calculate the net rate when both pipes are opened together. This is done by subtracting the emptying rate from the filling rate: (1/5) - (1/10).
  • Step 4: To subtract these fractions, find a common denominator. The common denominator for 5 and 10 is 10. Convert 1/5 to 2/10.
  • Step 5: Now subtract: (2/10) - (1/10) = 1/10. This means that together, both pipes fill 1/10 of the tank in one hour.
  • Step 6: To find out how long it takes to fill the entire tank, take the reciprocal of the net rate: 1 divided by (1/10) equals 10 hours.
  • Rate of Work – Understanding how to calculate the rate at which each pipe fills or empties the tank and how to combine these rates.
  • Net Rate Calculation – Determining the net effect of both pipes working together by subtracting the emptying rate from the filling rate.
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