A mixture of 50 liters contains 20% sugar. If 10 liters of the mixture is remove

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Question: A mixture of 50 liters contains 20% sugar. If 10 liters of the mixture is removed, how much sugar is left in the remaining mixture?

Options:

Correct Answer: 8 liters

Solution:

Initial sugar = 0.2 * 50 = 10 liters. Sugar in 10 liters removed = 0.2 * 10 = 2 liters. Remaining sugar = 10 - 2 = 8 liters.

A mixture of 50 liters contains 20% sugar. If 10 liters of the mixture is removed, how much sugar is left in the remaining mixture?

A mixture of 50 liters contains 20% sugar. If 10 liters of the mixture is removed, how much sugar is left in the remaining mixture?

Step 1: Calculate the total amount of sugar in the original 50 liters of mixture. Since the mixture is 20% sugar, multiply 50 liters by 0.2 (20%). This gives you 10 liters of sugar.
Step 2: Determine how much sugar is in the 10 liters of mixture that is removed. Since the mixture is still 20% sugar, multiply 10 liters by 0.2. This gives you 2 liters of sugar removed.
Step 3: Subtract the amount of sugar removed from the initial amount of sugar. Start with 10 liters of sugar and subtract the 2 liters that were removed. This gives you 8 liters of sugar left in the remaining mixture.

Percentage Calculation – Understanding how to calculate the amount of a substance in a mixture based on its percentage.
Mixture Removal – Calculating the effect of removing a portion of a mixture on the total amount of a substance.