Question: A container has 60 liters of a solution that is 15% acid. If 10 liters of this solution is replaced with water, what is the new percentage of acid in the solution?
Options:
Correct Answer: 10%
Solution:
Initial acid = 0.15 * 60 = 9 liters. After removing 10 liters, acid left = 9 - 0.15 * 10 = 7.5 liters. New volume = 60 liters. New percentage = (7.5/60) * 100 = 12.5%.