What is the energy of a photon with a frequency of 5 x 10^14 Hz?
Practice Questions
1 question
Q1
What is the energy of a photon with a frequency of 5 x 10^14 Hz?
3.1 x 10^-19 J
2.5 x 10^-19 J
4.0 x 10^-19 J
6.6 x 10^-19 J
The energy of a photon is given by E = hf. Using h = 6.63 x 10^-34 J.s, E = 6.63 x 10^-34 * 5 x 10^14 = 3.31 x 10^-19 J.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the energy of a photon with a frequency of 5 x 10^14 Hz?
Solution: The energy of a photon is given by E = hf. Using h = 6.63 x 10^-34 J.s, E = 6.63 x 10^-34 * 5 x 10^14 = 3.31 x 10^-19 J.
Steps: 7
Step 1: Understand that the energy of a photon can be calculated using the formula E = hf, where E is energy, h is Planck's constant, and f is frequency.
Step 2: Identify the value of Planck's constant (h), which is 6.63 x 10^-34 Joule seconds (J.s).
Step 3: Identify the frequency (f) of the photon, which is given as 5 x 10^14 Hz.
Step 4: Substitute the values into the formula: E = (6.63 x 10^-34 J.s) * (5 x 10^14 Hz).
Step 5: Perform the multiplication: 6.63 x 10^-34 * 5 = 3.315 x 10^-34.
Step 6: Adjust the exponent: 3.315 x 10^-34 * 10^14 = 3.31 x 10^-19 J.
Step 7: Conclude that the energy of the photon is 3.31 x 10^-19 Joules.
