Question: What is the critical load for a column with a length of 3 m, a moment of inertia of 0.0001 m^4, and a modulus of elasticity of 200 GPa?
Options:
Correct Answer: 1.96 kN
Solution:
The critical load P = (π² * E * I) / (L²). Substituting the values: P = (π² * 200e9 * 0.0001) / (3²) = 1.96 kN.