A steel rod with a diameter of 10 mm is subjected to a tensile force of 20 kN. W

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Question: A steel rod with a diameter of 10 mm is subjected to a tensile force of 20 kN. What is the stress in the rod?

Options:

Correct Answer: 159.15 MPa

Solution:

Stress = Force / Area. The area A = π(d/2)² = π(0.005)² = 7.85e-5 m². Stress = 20000 N / 7.85e-5 m² = 254647.91 Pa or 254.65 MPa.

A steel rod with a diameter of 10 mm is subjected to a tensile force of 20 kN. What is the stress in the rod?

A steel rod with a diameter of 10 mm is subjected to a tensile force of 20 kN. What is the stress in the rod?

Step 1: Identify the diameter of the steel rod, which is 10 mm.
Step 2: Convert the diameter from millimeters to meters. 10 mm = 0.01 m.
Step 3: Calculate the radius of the rod by dividing the diameter by 2. Radius = 0.01 m / 2 = 0.005 m.
Step 4: Use the formula for the area of a circle, A = π(r^2). Substitute the radius into the formula: A = π(0.005 m)².
Step 5: Calculate the area: A = π(0.000025 m²) ≈ 7.85e-5 m².
Step 6: Identify the tensile force applied to the rod, which is 20 kN. Convert this to Newtons: 20 kN = 20000 N.
Step 7: Use the formula for stress, which is Stress = Force / Area. Substitute the values: Stress = 20000 N / 7.85e-5 m².
Step 8: Calculate the stress: Stress ≈ 254647.91 Pa.
Step 9: Convert the stress from Pascals to Megapascals: 254647.91 Pa = 254.65 MPa.

Stress Calculation – Understanding how to calculate stress using the formula Stress = Force / Area.
Area of a Circle – Applying the formula for the area of a circle, A = π(d/2)², to find the cross-sectional area of the rod.