A 200 kg object is on a flat surface with a coefficient of kinetic friction of 0

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Question: A 200 kg object is on a flat surface with a coefficient of kinetic friction of 0.3. What is the force of friction acting on the object?

Options:

Correct Answer: 588 N

Solution:

The force of friction Ff = μk * N = 0.3 * (200 kg * 9.81 m/s²) = 588.6 N.

A 200 kg object is on a flat surface with a coefficient of kinetic friction of 0.3. What is the force of friction acting on the object?

A 200 kg object is on a flat surface with a coefficient of kinetic friction of 0.3. What is the force of friction acting on the object?

Step 1: Identify the mass of the object, which is 200 kg.
Step 2: Identify the coefficient of kinetic friction, which is 0.3.
Step 3: Calculate the normal force (N). The normal force on a flat surface is equal to the weight of the object, which is mass (m) times the acceleration due to gravity (g). Use g = 9.81 m/s².
Step 4: Calculate the weight of the object: N = m * g = 200 kg * 9.81 m/s².
Step 5: Calculate the normal force: N = 1962 N.
Step 6: Use the formula for the force of friction (Ff): Ff = μk * N.
Step 7: Substitute the values into the formula: Ff = 0.3 * 1962 N.
Step 8: Calculate the force of friction: Ff = 588.6 N.

Friction Force Calculation – This question tests the ability to calculate the force of kinetic friction using the coefficient of friction and the normal force.
Understanding Normal Force – It assesses the understanding of how to calculate the normal force acting on an object resting on a flat surface.