?
Categories
Account

What is the coefficient of static friction if a 50 kg box requires a force of 20

  • 📥 Instant PDF Download
  • ♾ Lifetime Access
  • 🛡 Secure & Original Content

What’s inside this PDF?

Question: What is the coefficient of static friction if a 50 kg box requires a force of 200 N to start moving?

Options:

  1. 0.4
  2. 0.5
  3. 0.6
  4. 0.7

Correct Answer: 0.5

Solution:

The coefficient of static friction (μs) can be calculated using the formula F = μs * N, where N is the normal force. Here, N = mg = 50 kg * 9.81 m/s² = 490.5 N. Thus, μs = F/N = 200 N / 490.5 N ≈ 0.4.

What is the coefficient of static friction if a 50 kg box requires a force of 20

Practice Questions

Q1
What is the coefficient of static friction if a 50 kg box requires a force of 200 N to start moving?
  1. 0.4
  2. 0.5
  3. 0.6
  4. 0.7

Questions & Step-by-Step Solutions

What is the coefficient of static friction if a 50 kg box requires a force of 200 N to start moving?
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely
Home Practice Performance eBooks