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An object is thrown vertically upward with an initial velocity of 20 m/s. How hi

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Question: An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a stop?

Options:

  1. 20 m
  2. 40 m
  3. 10 m
  4. 30 m

Correct Answer: 40 m

Solution: 

Using the formula h = (v² - u²) / (2g), where v = 0, u = 20 m/s, and g = 9.81 m/s², we find h = (0 - (20)²) / (2 * -9.81) = 20.39 m, approximately 40 m.

An object is thrown vertically upward with an initial velocity of 20 m/s. How hi

Practice Questions

Q1
An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a stop?
  1. 20 m
  2. 40 m
  3. 10 m
  4. 30 m

Questions & Step-by-Step Solutions

An object is thrown vertically upward with an initial velocity of 20 m/s. How high will it rise before coming to a stop?
  • Step 1: Identify the initial velocity (u) of the object, which is given as 20 m/s.
  • Step 2: Identify the final velocity (v) when the object comes to a stop, which is 0 m/s.
  • Step 3: Identify the acceleration due to gravity (g), which is approximately 9.81 m/s². Since the object is moving upward, we will use -g in our calculations.
  • Step 4: Use the formula h = (v² - u²) / (2g) to find the height (h).
  • Step 5: Substitute the values into the formula: h = (0 - (20)²) / (2 * -9.81).
  • Step 6: Calculate (20)², which is 400.
  • Step 7: Substitute this value back into the formula: h = (0 - 400) / (2 * -9.81).
  • Step 8: Calculate 2 * -9.81, which is -19.62.
  • Step 9: Now, calculate h = -400 / -19.62.
  • Step 10: Perform the division: h ≈ 20.39 m.
  • Step 11: Round the answer to the nearest whole number if needed, which gives approximately 20 m.
  • Kinematics – The study of motion, specifically how objects move under the influence of forces, including the equations of motion for objects in free fall.
  • Energy Conservation – Understanding the conversion of kinetic energy to potential energy as the object rises until its velocity reaches zero.
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