Question: A 10 kg block is sliding on a surface with a coefficient of kinetic friction of 0.3. What is the frictional force acting on the block?
Options:
Correct Answer: 30 N
Solution:
The frictional force can be calculated using F_friction = μ * N, where N = mg = 10 kg * 9.81 m/s² = 98.1 N. Thus, F_friction = 0.3 * 98.1 N = 29.43 N, approximately 30 N.