A coil with 100 turns is placed in a magnetic field that changes at a rate of 0.5 T/s. What is the induced EMF in the coil?
Practice Questions
1 question
Q1
A coil with 100 turns is placed in a magnetic field that changes at a rate of 0.5 T/s. What is the induced EMF in the coil?
50 V
100 V
200 V
25 V
Using Faraday's law, EMF = -N * (dΦ/dt) = -100 * 0.5 = -50 V. The induced EMF is 50 V.
Questions & Step-by-step Solutions
1 item
Q
Q: A coil with 100 turns is placed in a magnetic field that changes at a rate of 0.5 T/s. What is the induced EMF in the coil?
Solution: Using Faraday's law, EMF = -N * (dΦ/dt) = -100 * 0.5 = -50 V. The induced EMF is 50 V.
Steps: 6
Step 1: Understand that we need to find the induced EMF (electromotive force) in a coil.
Step 2: Know that the formula to calculate induced EMF is given by Faraday's law: EMF = -N * (dΦ/dt), where N is the number of turns in the coil and dΦ/dt is the rate of change of magnetic flux.
Step 3: Identify the values given in the question: N (number of turns) = 100 and dΦ/dt (rate of change of magnetic field) = 0.5 T/s.
Step 4: Substitute the values into the formula: EMF = -100 * 0.5.
Step 5: Calculate the result: -100 * 0.5 = -50 V.
Step 6: The negative sign indicates the direction of the induced EMF, but we are interested in the magnitude, which is 50 V.
