What is the magnetic field inside a long, ideal solenoid with n turns per unit l
Practice Questions
Q1
What is the magnetic field inside a long, ideal solenoid with n turns per unit length carrying a current I?
B = μ₀nI
B = μ₀I/n
B = nI/μ₀
B = μ₀I
Questions & Step-by-Step Solutions
What is the magnetic field inside a long, ideal solenoid with n turns per unit length carrying a current I?
Correct Answer: B = μ₀nI
Step 1: Understand what a solenoid is. A solenoid is a long coil of wire that creates a magnetic field when an electric current flows through it.
Step 2: Identify the key components of the solenoid. The number of turns of wire per unit length is represented by 'n', and the electric current flowing through the wire is represented by 'I'.
Step 3: Learn about the constant 'μ₀'. This is called the permeability of free space, and it is a constant value that helps us calculate the magnetic field.
Step 4: Use the formula for the magnetic field inside an ideal solenoid. The formula is B = μ₀nI, where B is the magnetic field strength.
Step 5: Plug in the values of 'n' (turns per unit length) and 'I' (current) into the formula to find the magnetic field inside the solenoid.
