If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
Practice Questions
1 question
Q1
If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
0 m/s
1 m/s
2 m/s
3 m/s
Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.
Questions & Step-by-step Solutions
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Q
Q: If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
Solution: Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.
Steps: 9
Step 1: Identify the mass of the object, which is 2 kg.
Step 2: Identify the initial velocity of the object, which is 3 m/s.
Step 3: Identify the force applied, which is 6 N in the opposite direction.
Step 4: Determine the net force acting on the object. Since the force is in the opposite direction, it will be -6 N.
Step 5: Calculate the acceleration using the formula: acceleration = net force / mass. Here, acceleration = -6 N / 2 kg = -3 m/s².
Step 6: Use the formula for final velocity: final velocity = initial velocity + (acceleration * time). Here, time is 2 seconds.
Step 7: Substitute the values: final velocity = 3 m/s + (-3 m/s² * 2 s).
Step 8: Calculate the final velocity: final velocity = 3 m/s - 6 m/s = -3 m/s.
Step 9: Since the final velocity is negative, it means the object is moving in the opposite direction.
