A ball is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

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20 m
40 m
10 m
80 m

Questions & Step-by-step Solutions

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Q: A ball is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

Solution: Using the formula v² = u² + 2as, where v = 0, u = 20 m/s, a = -9.8 m/s². 0 = (20)² + 2(-9.8)s, solving gives s = 20.4 m, approximately 40 m.

Steps: 9

Step 1: Identify the initial speed (u) of the ball, which is 20 m/s.
Step 2: Recognize that the final speed (v) at the highest point is 0 m/s because the ball comes to rest.
Step 3: Understand that the acceleration (a) due to gravity is -9.8 m/s² (negative because it acts downward).
Step 4: Use the formula v² = u² + 2as to find the height (s).
Step 5: Substitute the values into the formula: 0 = (20)² + 2(-9.8)s.
Step 6: Simplify the equation: 0 = 400 - 19.6s.
Step 7: Rearrange the equation to solve for s: 19.6s = 400.
Step 8: Divide both sides by 19.6 to find s: s = 400 / 19.6.
Step 9: Calculate the value of s, which is approximately 20.4 m.

A ball is thrown vertically upward with a speed of 20 m/s. How high will it rise before coming to rest?

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