A block of mass 5 kg is resting on a horizontal surface. If a horizontal force of 20 N is applied, what is the acceleration of the block? (Assume no friction)
Practice Questions
1 question
Q1
A block of mass 5 kg is resting on a horizontal surface. If a horizontal force of 20 N is applied, what is the acceleration of the block? (Assume no friction)
2 m/s²
4 m/s²
5 m/s²
10 m/s²
Using Newton's second law, F = ma, we have a = F/m = 20 N / 5 kg = 4 m/s².
Questions & Step-by-step Solutions
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Q
Q: A block of mass 5 kg is resting on a horizontal surface. If a horizontal force of 20 N is applied, what is the acceleration of the block? (Assume no friction)
Solution: Using Newton's second law, F = ma, we have a = F/m = 20 N / 5 kg = 4 m/s².
Steps: 6
Step 1: Identify the mass of the block, which is 5 kg.
Step 2: Identify the applied force, which is 20 N.
Step 3: Recall Newton's second law of motion, which states that Force (F) equals mass (m) times acceleration (a), or F = ma.
Step 4: Rearrange the formula to solve for acceleration (a): a = F/m.
Step 5: Substitute the values into the formula: a = 20 N / 5 kg.
