A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?
Practice Questions
1 question
Q1
A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?
10 m/s
15 m/s
20 m/s
5 m/s
Relative speed = Speed of cyclist - Speed of observer = 15 m/s - 5 m/s = 10 m/s.
Questions & Step-by-step Solutions
1 item
Q
Q: A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?
Solution: Relative speed = Speed of cyclist - Speed of observer = 15 m/s - 5 m/s = 10 m/s.
Steps: 5
Step 1: Identify the speed of the cyclist. The cyclist is moving at 15 m/s.
Step 2: Identify the speed of the observer. The observer starts moving at 5 m/s in the same direction as the cyclist.
Step 3: To find the speed of the cyclist relative to the observer, subtract the speed of the observer from the speed of the cyclist.
Step 4: Perform the calculation: 15 m/s (cyclist) - 5 m/s (observer) = 10 m/s.
Step 5: The result, 10 m/s, is the speed of the cyclist relative to the observer.
