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A cyclist is moving at 15 m/s and passes a stationary observer. If the observer

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Question: A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?

Options:

  1. 10 m/s
  2. 15 m/s
  3. 20 m/s
  4. 5 m/s

Correct Answer: 10 m/s

Solution: 

Relative speed = Speed of cyclist - Speed of observer = 15 m/s - 5 m/s = 10 m/s.

A cyclist is moving at 15 m/s and passes a stationary observer. If the observer

Practice Questions

Q1
A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?
  1. 10 m/s
  2. 15 m/s
  3. 20 m/s
  4. 5 m/s

Questions & Step-by-Step Solutions

A cyclist is moving at 15 m/s and passes a stationary observer. If the observer starts moving at 5 m/s in the same direction, what is the speed of the cyclist relative to the observer?
Correct Answer: 10 m/s
  • Step 1: Identify the speed of the cyclist. The cyclist is moving at 15 m/s.
  • Step 2: Identify the speed of the observer. The observer starts moving at 5 m/s in the same direction as the cyclist.
  • Step 3: To find the speed of the cyclist relative to the observer, subtract the speed of the observer from the speed of the cyclist.
  • Step 4: Perform the calculation: 15 m/s (cyclist) - 5 m/s (observer) = 10 m/s.
  • Step 5: The result, 10 m/s, is the speed of the cyclist relative to the observer.
  • Relative Speed – The speed of one object as observed from another moving object, calculated by subtracting the speed of the observer from the speed of the object being observed.
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