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A projectile is launched with an initial speed of 40 m/s at an angle of 30 degre
A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?
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Practice Questions
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Q1
A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?
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Time of flight (T) = (2u * sin(θ)) / g = (2 * 40 * (√3/2)) / 9.8 ≈ 6.1 s.
Questions & Step-by-step Solutions
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Q
Q: A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?
Solution:
Time of flight (T) = (2u * sin(θ)) / g = (2 * 40 * (√3/2)) / 9.8 ≈ 6.1 s.
Steps: 8
Show Steps
Step 1: Identify the initial speed (u) of the projectile, which is given as 40 m/s.
Step 2: Identify the angle of launch (θ), which is given as 30 degrees.
Step 3: Convert the angle from degrees to radians if necessary, but here we can use the sine directly.
Step 4: Calculate the sine of the angle: sin(30 degrees) = 1/2.
Step 5: Use the formula for time of flight: T = (2 * u * sin(θ)) / g.
Step 6: Substitute the values into the formula: T = (2 * 40 * (1/2)) / 9.8.
Step 7: Simplify the equation: T = (40) / 9.8.
Step 8: Calculate the final value: T ≈ 4.08 seconds.
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