A projectile is launched with an initial speed of 40 m/s at an angle of 30 degre

Practice Questions

Q1
A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?
  1. 4 s
  2. 5 s
  3. 6 s
  4. 8 s

Questions & Step-by-Step Solutions

A projectile is launched with an initial speed of 40 m/s at an angle of 30 degrees. What is the time of flight?
Correct Answer: 6.1 s
  • Step 1: Identify the initial speed (u) of the projectile, which is given as 40 m/s.
  • Step 2: Identify the angle of launch (θ), which is given as 30 degrees.
  • Step 3: Convert the angle from degrees to radians if necessary, but here we can use the sine directly.
  • Step 4: Calculate the sine of the angle: sin(30 degrees) = 1/2.
  • Step 5: Use the formula for time of flight: T = (2 * u * sin(θ)) / g.
  • Step 6: Substitute the values into the formula: T = (2 * 40 * (1/2)) / 9.8.
  • Step 7: Simplify the equation: T = (40) / 9.8.
  • Step 8: Calculate the final value: T ≈ 4.08 seconds.
  • Projectile Motion – The motion of an object thrown into the air, subject to gravitational acceleration, characterized by its initial speed and launch angle.
  • Time of Flight – The total time a projectile is in the air, calculated using the formula T = (2u * sin(θ)) / g, where u is the initial speed, θ is the launch angle, and g is the acceleration due to gravity.
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