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A ball is thrown at an angle of 45 degrees with an initial speed of 14 m/s. What
A ball is thrown at an angle of 45 degrees with an initial speed of 14 m/s. What is the range of the projectile?
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Practice Questions
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Q1
A ball is thrown at an angle of 45 degrees with an initial speed of 14 m/s. What is the range of the projectile?
10 m
14 m
20 m
28 m
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Range (R) = (u² * sin(2θ)) / g = (14² * 1) / 9.8 ≈ 20 m.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown at an angle of 45 degrees with an initial speed of 14 m/s. What is the range of the projectile?
Solution:
Range (R) = (u² * sin(2θ)) / g = (14² * 1) / 9.8 ≈ 20 m.
Steps: 8
Show Steps
Step 1: Identify the initial speed (u) of the ball, which is 14 m/s.
Step 2: Identify the angle of projection (θ), which is 45 degrees.
Step 3: Convert the angle to radians if necessary, but for 45 degrees, sin(2θ) = sin(90 degrees) = 1.
Step 4: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 5: Use the range formula for projectile motion: R = (u² * sin(2θ)) / g.
Step 6: Substitute the values into the formula: R = (14² * 1) / 9.8.
Step 7: Calculate 14², which is 196.
Step 8: Divide 196 by 9.8 to find the range: R ≈ 20 m.
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