A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and horizontal speed = 20 m/s)
Practice Questions
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Q1
A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and horizontal speed = 20 m/s)
20 m
40 m
60 m
80 m
Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 m/s * 4 s = 80 m.
Questions & Step-by-step Solutions
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Q
Q: A ball is thrown horizontally from the top of a cliff 80 m high. How far from the base of the cliff will it land? (Assume g = 10 m/s² and horizontal speed = 20 m/s)
Solution: Time to fall = √(2h/g) = √(2*80/10) = 4 s. Horizontal distance = speed * time = 20 m/s * 4 s = 80 m.
Steps: 8
Step 1: Identify the height of the cliff, which is 80 meters.
Step 2: Use the formula to calculate the time it takes for the ball to fall: time = √(2h/g), where h is the height and g is the acceleration due to gravity (10 m/s²).
Step 3: Plug in the values: time = √(2 * 80 / 10).
Step 4: Calculate the value inside the square root: 2 * 80 = 160, and 160 / 10 = 16.
Step 5: Find the square root of 16, which is 4 seconds. This is the time it takes for the ball to hit the ground.
Step 6: Now, calculate the horizontal distance the ball travels while it is falling. Use the formula: distance = speed * time.
Step 7: Plug in the values: distance = 20 m/s * 4 s.
Step 8: Calculate the distance: 20 * 4 = 80 meters. This is how far from the base of the cliff the ball will land.
