An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?
Practice Questions
1 question
Q1
An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?
45 m
90 m
135 m
180 m
Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Questions & Step-by-step Solutions
1 item
Q
Q: An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?
Solution: Using the formula: h = (v² - u²) / (2g), where v = 0 m/s, u = 30 m/s, g = 9.8 m/s². h = (0 - 30²) / (2 * -9.8) = 45.92 m, approximately 45 m.
Steps: 9
Step 1: Identify the initial speed (u) of the object. In this case, u = 30 m/s.
Step 2: Identify the final speed (v) of the object at the highest point. At the highest point, the speed is 0 m/s, so v = 0 m/s.
Step 3: Identify the acceleration due to gravity (g). This is a constant value of approximately 9.8 m/s², but since the object is moving upward, we will use -9.8 m/s² in our calculations.
Step 4: Use the formula for height (h) which is h = (v² - u²) / (2g).
Step 5: Substitute the values into the formula: h = (0² - 30²) / (2 * -9.8).
Step 6: Calculate 30², which is 900. So now we have h = (0 - 900) / (2 * -9.8).
Step 7: Calculate 2 * -9.8, which is -19.6. Now the equation looks like h = -900 / -19.6.
Step 8: Divide -900 by -19.6, which gives approximately 45.92 m.
Step 9: Round the answer to the nearest whole number, which is approximately 45 m.
