An object is thrown vertically upward with a speed of 30 m/s. How high will it r

An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?

An object is thrown vertically upward with a speed of 30 m/s. How high will it rise before coming to rest?

Correct Answer: 45 m

Step 1: Identify the initial speed (u) of the object. In this case, u = 30 m/s.
Step 2: Identify the final speed (v) of the object at the highest point. At the highest point, the speed is 0 m/s, so v = 0 m/s.
Step 3: Identify the acceleration due to gravity (g). This is a constant value of approximately 9.8 m/s², but since the object is moving upward, we will use -9.8 m/s² in our calculations.
Step 4: Use the formula for height (h) which is h = (v² - u²) / (2g).
Step 5: Substitute the values into the formula: h = (0² - 30²) / (2 * -9.8).
Step 6: Calculate 30², which is 900. So now we have h = (0 - 900) / (2 * -9.8).
Step 7: Calculate 2 * -9.8, which is -19.6. Now the equation looks like h = -900 / -19.6.
Step 8: Divide -900 by -19.6, which gives approximately 45.92 m.
Step 9: Round the answer to the nearest whole number, which is approximately 45 m.

Kinematics – The question tests the understanding of kinematic equations, specifically the relationship between initial velocity, final velocity, acceleration due to gravity, and displacement.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the peak of the object's trajectory.