If y = 5x^4 - 3x^3 + 2x - 1, find dy/dx at x = 1.

Practice Questions

Q1
If y = 5x^4 - 3x^3 + 2x - 1, find dy/dx at x = 1.
  1. 14
  2. 16
  3. 18
  4. 20

Questions & Step-by-Step Solutions

If y = 5x^4 - 3x^3 + 2x - 1, find dy/dx at x = 1.
Correct Answer: 13
  • Step 1: Identify the function given, which is y = 5x^4 - 3x^3 + 2x - 1.
  • Step 2: Differentiate the function with respect to x to find dy/dx. Use the power rule for each term.
  • Step 3: Apply the power rule: For 5x^4, the derivative is 20x^3; for -3x^3, the derivative is -9x^2; for 2x, the derivative is 2; and for -1, the derivative is 0.
  • Step 4: Combine the derivatives to get dy/dx = 20x^3 - 9x^2 + 2.
  • Step 5: Substitute x = 1 into the derivative: dy/dx = 20(1)^3 - 9(1)^2 + 2.
  • Step 6: Calculate the values: 20(1) = 20, -9(1) = -9, so dy/dx = 20 - 9 + 2.
  • Step 7: Simplify the expression: 20 - 9 = 11, then 11 + 2 = 13.
  • Step 8: Conclude that dy/dx at x = 1 is 13.
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