If y = (x^2 + 1)^5, find dy/dx at x = 1.

Practice Questions

Q1
If y = (x^2 + 1)^5, find dy/dx at x = 1.
  1. 10
  2. 20
  3. 30
  4. 40

Questions & Step-by-Step Solutions

If y = (x^2 + 1)^5, find dy/dx at x = 1.
Correct Answer: 160
  • Step 1: Identify the function y = (x^2 + 1)^5.
  • Step 2: Use the chain rule to find the derivative dy/dx. The chain rule states that if you have a function of a function, you multiply the derivative of the outer function by the derivative of the inner function.
  • Step 3: The outer function is (u)^5 where u = (x^2 + 1). The derivative of (u)^5 is 5u^4.
  • Step 4: The inner function u = (x^2 + 1). The derivative of u with respect to x is 2x.
  • Step 5: Combine the derivatives using the chain rule: dy/dx = 5(x^2 + 1)^4 * (2x).
  • Step 6: Substitute x = 1 into the derivative: dy/dx = 5((1)^2 + 1)^4 * (2(1)).
  • Step 7: Calculate (1)^2 + 1 = 2, so dy/dx = 5(2)^4 * 2.
  • Step 8: Calculate (2)^4 = 16, so dy/dx = 5 * 16 * 2.
  • Step 9: Finally, calculate 5 * 16 * 2 = 160.
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