What is the work done in moving a charge of +2μC through a potential difference

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Question: What is the work done in moving a charge of +2μC through a potential difference of 10V?

Options:

Correct Answer: 200 μJ

Solution:

W = q * V = 2 × 10^-6 C * 10 V = 20 × 10^-6 J = 20 μJ.

What is the work done in moving a charge of +2μC through a potential difference of 10V?

What is the work done in moving a charge of +2μC through a potential difference of 10V?

Correct Answer: 20 μJ

Step 1: Identify the charge being moved. In this case, it is +2μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. +2μC is equal to 2 × 10^-6 C.
Step 3: Identify the potential difference through which the charge is moved. Here, it is 10V (volts).
Step 4: Use the formula for work done (W) which is W = q * V, where q is the charge and V is the potential difference.
Step 5: Substitute the values into the formula: W = (2 × 10^-6 C) * (10 V).
Step 6: Calculate the result: W = 20 × 10^-6 J (joules).
Step 7: Convert the result to microjoules: 20 × 10^-6 J is equal to 20 μJ.

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