If a charge of +4μC is placed in an electric field of 500 N/C, what is the force

If a charge of +4μC is placed in an electric field of 500 N/C, what is the force acting on the charge?

If a charge of +4μC is placed in an electric field of 500 N/C, what is the force acting on the charge?

Correct Answer: 2 N

Step 1: Identify the charge (q) given in the problem. It is +4μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. 1μC = 10^-6 C, so +4μC = 4 × 10^-6 C.
Step 3: Identify the electric field strength (E) given in the problem. It is 500 N/C (newtons per coulomb).
Step 4: Use the formula for force (F) acting on a charge in an electric field: F = q * E.
Step 5: Substitute the values into the formula: F = (4 × 10^-6 C) * (500 N/C).
Step 6: Calculate the force: F = 2 N.

Electric Force Calculation – The question tests the ability to calculate the force acting on a charge in an electric field using the formula F = q * E.
Units of Measurement – Understanding the units involved (Coulombs for charge and Newtons per Coulomb for electric field) is essential for correct calculations.