A capacitor of capacitance 10μF is charged to a potential difference of 100V. Wh

₹0.0

Question: A capacitor of capacitance 10μF is charged to a potential difference of 100V. What is the energy stored in the capacitor?

Options:

Correct Answer: 0.1 J

Solution:

Energy stored, U = 1/2 * C * V^2 = 1/2 * 10 × 10^-6 * (100)^2 = 0.05 J.

A capacitor of capacitance 10μF is charged to a potential difference of 100V. What is the energy stored in the capacitor?

A capacitor of capacitance 10μF is charged to a potential difference of 100V. What is the energy stored in the capacitor?

Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 * C * V^2.
Step 2: Identify the values given in the problem: capacitance (C) = 10μF and potential difference (V) = 100V.
Step 3: Convert the capacitance from microfarads to farads: 10μF = 10 × 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6) * (100)^2.
Step 5: Calculate (100)^2, which equals 10000.
Step 6: Multiply 10 × 10^-6 by 10000, which equals 0.1.
Step 7: Multiply 0.1 by 1/2, which equals 0.05.
Step 8: Conclude that the energy stored in the capacitor is 0.05 J.

Capacitance – Capacitance is the ability of a capacitor to store charge per unit voltage.
Energy Stored in a Capacitor – The energy stored in a capacitor can be calculated using the formula U = 1/2 * C * V^2.