A capacitor of capacitance 10μF is charged to a potential difference of 100V. Wh

Practice Questions

Q1
A capacitor of capacitance 10μF is charged to a potential difference of 100V. What is the energy stored in the capacitor?
  1. 0.05 J
  2. 0.1 J
  3. 0.2 J
  4. 0.3 J

Questions & Step-by-Step Solutions

A capacitor of capacitance 10μF is charged to a potential difference of 100V. What is the energy stored in the capacitor?
  • Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 * C * V^2.
  • Step 2: Identify the values given in the problem: capacitance (C) = 10μF and potential difference (V) = 100V.
  • Step 3: Convert the capacitance from microfarads to farads: 10μF = 10 × 10^-6 F.
  • Step 4: Substitute the values into the formula: U = 1/2 * (10 × 10^-6) * (100)^2.
  • Step 5: Calculate (100)^2, which equals 10000.
  • Step 6: Multiply 10 × 10^-6 by 10000, which equals 0.1.
  • Step 7: Multiply 0.1 by 1/2, which equals 0.05.
  • Step 8: Conclude that the energy stored in the capacitor is 0.05 J.
  • Capacitance – Capacitance is the ability of a capacitor to store charge per unit voltage.
  • Energy Stored in a Capacitor – The energy stored in a capacitor can be calculated using the formula U = 1/2 * C * V^2.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely