In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?

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Q: In a circuit with a 24V battery and two resistors in series (6Ω and 3Ω), what is the voltage across the 3Ω resistor?

Solution: Total resistance = 6Ω + 3Ω = 9Ω. Current I = V / R = 24V / 9Ω = 2.67A. Voltage across 3Ω = I * R = 2.67A * 3Ω = 8V.

Steps: 6

Step 1: Identify the total resistance in the circuit by adding the resistances of the two resistors. Total resistance = 6Ω + 3Ω.
Step 2: Calculate the total resistance. Total resistance = 9Ω.
Step 3: Use Ohm's Law to find the current in the circuit. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R). Here, V = 24V and R = 9Ω.
Step 4: Calculate the current. I = 24V / 9Ω = 2.67A.
Step 5: To find the voltage across the 3Ω resistor, use the formula Voltage (V) = Current (I) * Resistance (R). Here, I = 2.67A and R = 3Ω.
Step 6: Calculate the voltage across the 3Ω resistor. Voltage = 2.67A * 3Ω = 8V.