A boat can travel at 18 km/h in still water. If it takes 4 hours to go upstream

Practice Questions

Q1
A boat can travel at 18 km/h in still water. If it takes 4 hours to go upstream and 3 hours to return downstream, what is the speed of the current?
  1. 2 km/h
  2. 3 km/h
  3. 4 km/h
  4. 5 km/h

Questions & Step-by-Step Solutions

A boat can travel at 18 km/h in still water. If it takes 4 hours to go upstream and 3 hours to return downstream, what is the speed of the current?
Correct Answer: 3 km/h
  • Step 1: Understand that the boat's speed in still water is 18 km/h.
  • Step 2: Define the speed of the current as 'x'.
  • Step 3: When the boat goes upstream (against the current), its effective speed is 18 - x km/h.
  • Step 4: When the boat goes downstream (with the current), its effective speed is 18 + x km/h.
  • Step 5: The time taken to go upstream is 4 hours, so the distance traveled upstream is 4 hours * (18 - x) km/h.
  • Step 6: The time taken to return downstream is 3 hours, so the distance traveled downstream is 3 hours * (18 + x) km/h.
  • Step 7: Since the distance traveled upstream and downstream is the same, set the two distance equations equal: 4(18 - x) = 3(18 + x).
  • Step 8: Expand both sides of the equation: 72 - 4x = 54 + 3x.
  • Step 9: Rearrange the equation to isolate 'x': 72 - 54 = 4x + 3x.
  • Step 10: Simplify the equation: 18 = 7x.
  • Step 11: Solve for 'x' by dividing both sides by 7: x = 18 / 7.
  • Step 12: Calculate the value of 'x' to find the speed of the current: x = 3 km/h.
  • Relative Speed – Understanding how to calculate effective speeds when moving against and with a current.
  • Distance, Speed, Time Relationship – Applying the formula distance = speed × time to relate the distances traveled upstream and downstream.
  • Algebraic Manipulation – Solving equations involving variables to find the unknown speed of the current.
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