If a man walks 5 km towards the north and then turns east and walks 3 km, how fa

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Question: If a man walks 5 km towards the north and then turns east and walks 3 km, how far is he from the starting point?

Options:

Correct Answer: 8 km

Solution:

Using Pythagorean theorem: distance = √(5^2 + 3^2) = √34 ≈ 8 km.

If a man walks 5 km towards the north and then turns east and walks 3 km, how far is he from the starting point?

If a man walks 5 km towards the north and then turns east and walks 3 km, how far is he from the starting point?

Step 1: The man starts at a point, which we will call the starting point.
Step 2: He walks 5 km north. Now he is 5 km away from the starting point in the north direction.
Step 3: Next, he turns east and walks 3 km. Now he is 3 km away from the point where he turned, but still 5 km north from the starting point.
Step 4: To find out how far he is from the starting point, we can imagine a right triangle where one side is 5 km (north) and the other side is 3 km (east).
Step 5: We use the Pythagorean theorem, which says that the square of the hypotenuse (the distance from the starting point) is equal to the sum of the squares of the other two sides.
Step 6: We calculate the squares: 5^2 = 25 and 3^2 = 9.
Step 7: We add these two results together: 25 + 9 = 34.
Step 8: Now, we take the square root of 34 to find the distance: √34.
Step 9: The approximate value of √34 is about 5.83 km.

Pythagorean Theorem – The theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.