Question: Find the angle between the vectors A = (1, 2, 2) and B = (2, 1, 1).
Options:
Correct Answer: 45°
Solution:
cos(θ) = (A · B) / (|A| |B|). A · B = 1*2 + 2*1 + 2*1 = 6; |A| = √(1^2 + 2^2 + 2^2) = 3; |B| = √(2^2 + 1^2 + 1^2) = √6. Thus, cos(θ) = 6 / (3√6) = 1/√6, θ = 45°.