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If a person walks 5 km north, then 3 km east, and finally 4 km south, what is th

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Question: If a person walks 5 km north, then 3 km east, and finally 4 km south, what is the shortest distance from the starting point?

Options:

  1. 2 km
  2. 3 km
  3. 4 km
  4. 5 km

Correct Answer: 3 km

Solution:

The person ends up 2 km north and 3 km east of the starting point. Using the Pythagorean theorem, the shortest distance is √(2^2 + 3^2) = √13, which is approximately 3.6 km.

If a person walks 5 km north, then 3 km east, and finally 4 km south, what is th

Practice Questions

Q1
If a person walks 5 km north, then 3 km east, and finally 4 km south, what is the shortest distance from the starting point?
  1. 2 km
  2. 3 km
  3. 4 km
  4. 5 km

Questions & Step-by-Step Solutions

If a person walks 5 km north, then 3 km east, and finally 4 km south, what is the shortest distance from the starting point?
  • Step 1: Start at the initial point (0, 0) on a coordinate grid.
  • Step 2: Walk 5 km north. This moves you to the point (0, 5).
  • Step 3: Walk 3 km east. This moves you to the point (3, 5).
  • Step 4: Walk 4 km south. This moves you to the point (3, 1).
  • Step 5: Calculate the distance from the final point (3, 1) to the starting point (0, 0).
  • Step 6: Find the difference in the north-south direction: 1 - 0 = 1 km (north) and the east-west direction: 3 - 0 = 3 km (east).
  • Step 7: Use the Pythagorean theorem to find the shortest distance: distance = √(1^2 + 3^2).
  • Step 8: Calculate 1^2 = 1 and 3^2 = 9, then add them: 1 + 9 = 10.
  • Step 9: Take the square root of 10 to find the distance: √10, which is approximately 3.16 km.
  • Vector Addition – Understanding how to combine movements in different directions to find a resultant position.
  • Pythagorean Theorem – Applying the theorem to calculate the shortest distance between two points in a Cartesian plane.
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