A box contains 10 balls, 4 of which are red and 6 are blue. If one ball is drawn at random, what is the probability that it is not blue?
Practice Questions
1 question
Q1
A box contains 10 balls, 4 of which are red and 6 are blue. If one ball is drawn at random, what is the probability that it is not blue?
2/5
3/5
4/10
1/5
The probability of not drawing a blue ball = Number of red balls / Total balls = 4/10 = 2/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A box contains 10 balls, 4 of which are red and 6 are blue. If one ball is drawn at random, what is the probability that it is not blue?
Solution: The probability of not drawing a blue ball = Number of red balls / Total balls = 4/10 = 2/5.
Steps: 5
Step 1: Identify the total number of balls in the box. There are 10 balls in total.
Step 2: Identify how many of those balls are red. There are 4 red balls.
Step 3: Determine how many balls are not blue. Since there are 4 red balls, the number of balls that are not blue is 4.
Step 4: Calculate the probability of drawing a ball that is not blue. This is done by dividing the number of red balls by the total number of balls: 4 (red balls) / 10 (total balls).
