A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
Practice Questions
1 question
Q1
A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
4/15
3/5
9/15
1/3
Total marbles = 4 + 5 + 6 = 15. Probability of red or green = (4 + 5)/15 = 9/15 = 3/5.
Questions & Step-by-step Solutions
1 item
Q
Q: A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is either red or green?
Solution: Total marbles = 4 + 5 + 6 = 15. Probability of red or green = (4 + 5)/15 = 9/15 = 3/5.
Steps: 7
Step 1: Count the number of red marbles. There are 4 red marbles.
Step 2: Count the number of green marbles. There are 5 green marbles.
Step 3: Count the number of blue marbles. There are 6 blue marbles.
Step 4: Add the total number of marbles together: 4 (red) + 5 (green) + 6 (blue) = 15 total marbles.
Step 5: Add the number of red and green marbles together: 4 (red) + 5 (green) = 9 marbles that are either red or green.
Step 6: To find the probability of drawing a red or green marble, divide the number of red or green marbles by the total number of marbles: 9 (red or green) / 15 (total) = 9/15.
Step 7: Simplify the fraction 9/15 to its lowest terms: 9/15 = 3/5.
