Step 8: Calculate the factorials: 5! = 120, 3! = 6, and 2! = 2.
Step 9: Substitute the factorials into the formula: C(5, 3) = 120 / (6 * 2) = 120 / 12 = 10.
Step 10: Conclude that there are 10 subsets of G that have exactly 3 elements.
Combinations – The concept of combinations is used to determine the number of ways to choose a subset of items from a larger set without regard to the order of selection.