In a rhombus, if one diagonal measures 12 cm and the other measures 16 cm, what

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Question: In a rhombus, if one diagonal measures 12 cm and the other measures 16 cm, what is the area of the rhombus?

Options:

Correct Answer: 96 cm²

Solution:

The area of a rhombus can be calculated using the formula: Area = (d1 × d2) / 2. Here, Area = (12 cm × 16 cm) / 2 = 96 cm².

In a rhombus, if one diagonal measures 12 cm and the other measures 16 cm, what is the area of the rhombus?

In a rhombus, if one diagonal measures 12 cm and the other measures 16 cm, what is the area of the rhombus?

Step 1: Identify the lengths of the diagonals of the rhombus. In this case, one diagonal (d1) is 12 cm and the other diagonal (d2) is 16 cm.
Step 2: Use the formula for the area of a rhombus, which is Area = (d1 × d2) / 2.
Step 3: Substitute the values of the diagonals into the formula: Area = (12 cm × 16 cm) / 2.
Step 4: Calculate the product of the diagonals: 12 cm × 16 cm = 192 cm².
Step 5: Divide the result by 2 to find the area: 192 cm² / 2 = 96 cm².
Step 6: Conclude that the area of the rhombus is 96 cm².

Area of a Rhombus – The area of a rhombus can be calculated using the formula: Area = (d1 × d2) / 2, where d1 and d2 are the lengths of the diagonals.