Question: What is the area of an isosceles triangle with a base of 10 cm and equal sides of 13 cm?
Options:
Correct Answer: 65 cm²
Solution:
Using Heron\'s formula, s = (10 + 13 + 13) / 2 = 18. Area = √(s(s-a)(s-b)(s-c)) = √(18(18-10)(18-13)(18-13)) = √(18*8*5*5) = 60 cm².