Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.

Practice Questions

1 question
Q1
Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.
  1. y = x^2 + 1
  2. y = x^2 - 1
  3. y = 2x + 1
  4. y = 2x - 1

Questions & Step-by-step Solutions

1 item
Q
Q: Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.
Solution: Integrating gives y = x^2 + C. Using the initial condition y(0) = 1, we find C = 1.
Steps: 8

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