Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.

₹0.0

Question: Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.

Options:

Correct Answer: y = x^2 + 1

Solution:

Integrating gives y = x^2 + C. Using the initial condition y(0) = 1, we find C = 1.

Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.

Find the particular solution of dy/dx = 2x with the initial condition y(0) = 1.

Correct Answer: y = x^2 + 1

Step 1: Start with the differential equation dy/dx = 2x.
Step 2: Integrate both sides with respect to x. This means we find the integral of 2x.
Step 3: The integral of 2x is x^2 + C, where C is a constant.
Step 4: Now we have the general solution: y = x^2 + C.
Step 5: Use the initial condition y(0) = 1 to find the value of C.
Step 6: Substitute x = 0 into the equation: y(0) = 0^2 + C = C.
Step 7: Set C equal to 1 because y(0) = 1.
Step 8: Now we have the particular solution: y = x^2 + 1.

Differential Equations – The question tests the ability to solve a first-order ordinary differential equation using integration.
Initial Conditions – The question assesses the understanding of how to apply initial conditions to find the particular solution.