Question: What is the value of k if the equation x^2 + kx + 16 = 0 has one real solution?

Options:

1. k = 8
2. k = -8
3. k = 0
4. k = 4

Correct Answer: k = -8

Solution:

For one real solution, the discriminant must be zero: k^2 - 4(1)(16) = 0. Thus, k^2 = 64, so k = ±8.