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What is the equation of the line perpendicular to y = 3x + 1 that passes through

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Question: What is the equation of the line perpendicular to y = 3x + 1 that passes through the point (2, 5)?

Options:

  1. y = -1/3x + 7
  2. y = 3x - 1
  3. y = -3x + 11
  4. y = 1/3x + 3

Correct Answer: y = -1/3x + 7

Solution:

The slope of the given line is 3.\\nThe slope of the perpendicular line is -1/3.\\nUsing point-slope form: y - 5 = -1/3(x - 2) gives y = -1/3x + 7.

What is the equation of the line perpendicular to y = 3x + 1 that passes through

Practice Questions

Q1
What is the equation of the line perpendicular to y = 3x + 1 that passes through the point (2, 5)?
  1. y = -1/3x + 7
  2. y = 3x - 1
  3. y = -3x + 11
  4. y = 1/3x + 3

Questions & Step-by-Step Solutions

What is the equation of the line perpendicular to y = 3x + 1 that passes through the point (2, 5)?
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