Question: What is the sum of the first 6 terms of the geometric progression 1, 3, 9, ...?
Options:
Correct Answer: 364
Solution:
The first term a = 1, and the common ratio r = 3. The sum of the first n terms of a GP is S_n = a(1 - r^n) / (1 - r). For n = 6, S_6 = 1(1 - 3^6) / (1 - 3) = (1 - 729) / -2 = -728 / -2 = 364.
