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Solve for x: 2sin(x) = √3, where 0 ≤ x < 360°.

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Question: Solve for x: 2sin(x) = √3, where 0 ≤ x < 360°.

Options:

  1. 30°
  2. 150°
  3. 210°
  4. 330°

Correct Answer: 150°

Solution: 

sin(x) = √3/2 gives x = 60° and 120°, so 2sin(x) = √3 gives x = 150°.

Solve for x: 2sin(x) = √3, where 0 ≤ x < 360°.

Practice Questions

Q1
Solve for x: 2sin(x) = √3, where 0 ≤ x < 360°.
  1. 30°
  2. 150°
  3. 210°
  4. 330°

Questions & Step-by-Step Solutions

Solve for x: 2sin(x) = √3, where 0 ≤ x < 360°.
  • Trigonometric Equations – The question tests the ability to solve basic trigonometric equations involving the sine function.
  • Unit Circle – Understanding the unit circle is essential for identifying angles corresponding to specific sine values.
  • Quadrants of the Unit Circle – Recognizing that sine is positive in the first and second quadrants is crucial for finding all solutions.
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