Question: What is the distance from the point (1, -1) to the line 2x + 3y - 6 = 0?
Options:
Correct Answer: 2
Solution:
Distance = |Ax1 + By1 + C| / √(A² + B²) = |2*1 + 3*(-1) - 6| / √(2² + 3²) = |-7| / √13 = 7/√13.