Question: What is the area of a triangle with vertices at (0, 0), (b, 0), and (b/2, h)?
Options:
(bh)/2
(b^2h)/2
(b^2)/2
(bh)/4
Correct Answer: (bh)/2
Solution:
Area = 1/2 * base * height = 1/2 * b * h = (bh)/2.
What is the area of a triangle with vertices at (0, 0), (b, 0), and (b/2, h)?
Practice Questions
Q1
What is the area of a triangle with vertices at (0, 0), (b, 0), and (b/2, h)?
(bh)/2
(b^2h)/2
(b^2)/2
(bh)/4
Questions & Step-by-Step Solutions
What is the area of a triangle with vertices at (0, 0), (b, 0), and (b/2, h)?
Area of a Triangle – The area of a triangle can be calculated using the formula Area = 1/2 * base * height, where the base and height are perpendicular to each other.
Coordinate Geometry – Understanding how to determine the base and height of a triangle given its vertices in a coordinate plane.
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