Question: What is the distance from the point (3, 2) to the line 2x + 3y - 6 = 0?

Options:

1. 1
2. 2
3. 3
4. 4

Correct Answer: 2

Solution:

Distance from point (x0, y0) to line Ax + By + C = 0 is given by |Ax0 + By0 + C| / √(A² + B²). Here, A=2, B=3, C=-6. Distance = |2*3 + 3*2 - 6| / √(2² + 3²) = |6 + 6 - 6| / √(4 + 9) = 6 / √13 ≈ 1.67, which rounds to 2.