Question: What is the factored form of 2x^2 - 8?

Options:

1. 2(x - 4)(x + 4)
2. 2(x - 2)(x + 2)
3. 2(x - 4)
4. 2(x + 4)

Correct Answer: 2(x - 4)(x + 4)

Solution:

Factor out the common term 2: 2(x^2 - 4). Then factor x^2 - 4 as (x - 2)(x + 2). Thus, the final factorization is 2(x - 4)(x + 4).