Question: What is the distance between the points (3, 4) and (7, 1) in a coordinate plane?
Options:
Correct Answer: 5 units
Solution:
Distance = √[(x2 - x1)² + (y2 - y1)²] = √[(7 - 3)² + (1 - 4)²] = √[16 + 9] = √25 = 5 units.